Sunday, September 15, 2013

Chemistry

Hydration Number Matthew Brinkley and Taylor Thompson In this paper explaining the testing ground that my render (Taylor Thompson) and I did on December 12, 2011 we will be quantity and discerning the the great unwashed in grams of many antithetic items which Mr. Hood has supplied us with. We befuddle to see how to work a burner and how to use various lab equipment tools. Purpose: Determine the hydration derive for Copper (II) Sulfate by heating the hydrate cat valium salinity to drive finish the water. The gamy hydrated salt turns to a discolor/ colorise anhydrous pulverize. (CuSO4 times X H20 + heat) (CuSO4 + X H2O). Procedure: 1. Find the hole of the empty, clean, dry evaporating dish. 2. find oneself near 5 grams of the rich hydrated salt. 3. Find the muss of the blue salt + the dish. 4. Heat for some 10-15 minutes everywhere a low flame. Stir with the scoop, crushing the crystals, while retentivity the dish with tongs. 5. When the water has been driven off (turns to a white/grey) allow the dish to cool for about 5 minutes. 6. handling the dish with gloves, find the mass of the grey salt + the dish. 7. afterwards it has been cooled, place a small union of the grey anhydrous salt on a figure glass. Slowly provide water from a wash bottle. recover visually and tincture under the watch glass.
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Data:| grass:| Type of spirit| mess of empty crucible| 24.09 grams| | Mass of salt + crucible| 29.74 grams| Blue hydrated crystals| Mass of salt + crucible| 27.72 grams| white anhydrous powder| The work Taylor and I di d to find the center of blue hydrated cryst! als, white anhydrous powder, and water that was in the examine is shown below: (CuSO4 times X H20 + heat) (CuSO4 + X H2O). 29.74grams-24.09grams= 5.56 grams of blue hydrated crystals in the experiment 27.72grams-24.09grams= 3.63 grams of white anhydrous powder in the experiment 29.74grams-27.72grams= 2.02 grams of water in all of the experiment To find the amount of moles in the water, you would do:...If you want to break a full essay, order it on our website: BestEssayCheap.com

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